In function `void test ()': `exit' undeclared - C (СИ)

#include <stdio.h>

/* Masks for the shift registers */
#define R1MASK  0x07FFFF /* 19 bits, numbered 0..18 */
#define R2MASK  0x3FFFFF /* 22 bits, numbered 0..21 */
#define R3MASK  0x7FFFFF /* 23 bits, numbered 0..22 */
#ifdef A5_2
#define R4MASK  0x01FFFF /* 17 bits, numbered 0..16 */
#endif /* A5_2 */

#ifndef A5_2
/* Middle bit of each of the three shift registers, for clock control */
#define R1MID   0x000100 /* bit 8 */
#define R2MID   0x000400 /* bit 10 */
#define R3MID   0x000400 /* bit 10 */
#else /* A5_2 */
/* A bit of R4 that controls each of the shift registers */
#define R4TAP1  0x000400 /* bit 10 */
#define R4TAP2  0x000008 /* bit 3 */
#define R4TAP3  0x000080 /* bit 7 */
#endif /* A5_2 */

/* Feedback taps, for clocking the shift registers.
 * These correspond to the primitive polynomials
 * x^19 + x^5 + x^2 + x + 1, x^22 + x + 1,
 * x^23 + x^15 + x^2 + x + 1, and x^17 + x^5 + 1. */

#define R1TAPS  0x072000 /* bits 18,17,16,13 */
#define R2TAPS  0x300000 /* bits 21,20 */
#define R3TAPS  0x700080 /* bits 22,21,20,7 */
#ifdef A5_2
#define R4TAPS  0x010800 /* bits 16,11 */
#endif /* A5_2 */

typedef unsigned char byte;
typedef unsigned long word;
typedef word bit;

/* Calculate the parity of a 32-bit word, i.e. the sum of its bits modulo 2
*/
bit parity(word x) {
        x ^= x>>16;
        x ^= x>>8;
        x ^= x>>4;
        x ^= x>>2;
        x ^= x>>1;
        return x&1;
}

/* Clock one shift register.  For A5/2, when the last bit of the frame
 * is loaded in, one particular bit of each register is forced to '1';
 * that bit is passed in as the last argument. */
#ifndef A5_2
word clockone(word reg, word mask, word taps) {
#else /* A5_2 */
word clockone(word reg, word mask, word taps, word loaded_bit) {
#endif /* A5_2 */
        word t = reg & taps;
        reg = (reg << 1) & mask;
        reg |= parity(t);
#ifdef A5_2
        reg |= loaded_bit;
#endif /* A5_2 */
        return reg;
}

/* The three shift registers.  They're in global variables to make the code
 * easier to understand.
 * A better implementation would not use global variables. */
word R1, R2, R3;
#ifdef A5_2
word R4;
#endif /* A5_2 */

/* Return 1 iff at least two of the parameter words are non-zero. */
bit majority(word w1, word w2, word w3) {
        int sum = (w1 != 0) + (w2 != 0) + (w3 != 0);
        if (sum >= 2)
                return 1;
        else
                return 0;
}

/* Clock two or three of R1,R2,R3, with clock control
 * according to their middle bits.
 * Specifically, we clock Ri whenever Ri's middle bit
 * agrees with the majority value of the three middle bits.  For A5/2,
 * use particular bits of R4 instead of the middle bits.  Also, for A5/2,
 * always clock R4.
 * If allP == 1, clock all three of R1,R2,R3, ignoring their middle bits.
 * This is only used for key setup.  If loaded == 1, then this is the last
 * bit of the frame number, and if we're doing A5/2, we have to set a
 * particular bit in each of the four registers. */
void clock(int allP, int loaded) {
#ifndef A5_2
        bit maj = majority(R1&R1MID, R2&R2MID, R3&R3MID);
        if (allP || (((R1&R1MID)!=0) == maj))
                R1 = clockone(R1, R1MASK, R1TAPS);
        if (allP || (((R2&R2MID)!=0) == maj))
                R2 = clockone(R2, R2MASK, R2TAPS);
        if (allP || (((R3&R3MID)!=0) == maj))
                R3 = clockone(R3, R3MASK, R3TAPS);
#else /* A5_2 */
        bit maj = majority(R4&R4TAP1, R4&R4TAP2, R4&R4TAP3);
        if (allP || (((R4&R4TAP1)!=0) == maj))
                R1 = clockone(R1, R1MASK, R1TAPS, loaded<<15);
        if (allP || (((R4&R4TAP2)!=0) == maj))
                R2 = clockone(R2, R2MASK, R2TAPS, loaded<<16);
        if (allP || (((R4&R4TAP3)!=0) == maj))
                R3 = clockone(R3, R3MASK, R3TAPS, loaded<<18);
        R4 = clockone(R4, R4MASK, R4TAPS, loaded<<10);
#endif /* A5_2 */
}

/* Generate an output bit from the current state.
 * You grab a bit from each register via the output generation taps;
 * then you XOR the resulting three bits.  For A5/2, in addition to
 * the top bit of each of R1,R2,R3, also XOR in a majority function
 * of three particular bits of the register (one of them complemented)
 * to make it non-linear.  Also, for A5/2, delay the output by one
 * clock cycle for some reason. */
bit getbit() {
        bit topbits = (((R1 >> 18) ^ (R2 >> 21) ^ (R3 >> 22)) & 0x01);
#ifndef A5_2
        return topbits;
#else /* A5_2 */
        static bit delaybit = 0;
        bit nowbit = delaybit;
        delaybit = (
            topbits
            ^ majority(R1&0x8000, (~R1)&0x4000, R1&0x1000)
            ^ majority((~R2)&0x10000, R2&0x2000, R2&0x200)
            ^ majority(R3&0x40000, R3&0x10000, (~R3)&0x2000)
            );
        return nowbit;
#endif /* A5_2 */
}

/* Do the A5 key setup.  This routine accepts a 64-bit key and
 * a 22-bit frame number. */
void keysetup(byte key[8], word frame) {
        int i;
        bit keybit, framebit;

        /* Zero out the shift registers. */
        R1 = R2 = R3 = 0;
#ifdef A5_2
        R4 = 0;
#endif /* A5_2 */

        /* Load the key into the shift registers,
         * LSB of first byte of key array first,
         * clocking each register once for every
         * key bit loaded.  (The usual clock
         * control rule is temporarily disabled.) */
        for (i=0; i<64; i++) {
                clock(1,0); /* always clock */
                keybit = (key[i/8] >> (i&7)) & 1; /* The i-th bit of the key */
                R1 ^= keybit; R2 ^= keybit; R3 ^= keybit;
#ifdef A5_2
                R4 ^= keybit;
#endif /* A5_2 */
        }

        /* Load the frame number into the shift registers, LSB first,
         * clocking each register once for every key bit loaded.
         * (The usual clock control rule is still disabled.)
         * For A5/2, signal when the last bit is being clocked in. */
        for (i=0; i<22; i++) {
                clock(1,i==21); /* always clock */
                framebit = (frame >> i) & 1; /* The i-th bit of the frame # */
                R1 ^= framebit; R2 ^= framebit; R3 ^= framebit;
#ifdef A5_2
                R4 ^= framebit;
#endif /* A5_2 */
        }

        /* Run the shift registers for 100 clocks
         * to mix the keying material and frame number
         * together with output generation disabled,
         * so that there is sufficient avalanche.
         * We re-enable the majority-based clock control
         * rule from now on. */
        for (i=0; i<100; i++) {
                clock(0,0);
        }
        /* For A5/2, we have to load the delayed output bit.  This does _not_
         * change the state of the registers.  For A5/1, this is a no-op. */
        getbit();

        /* Now the key is properly set up. */
}

/* Generate output.  We generate 228 bits of
 * keystream output.  The first 114 bits is for
 * the A->B frame; the next 114 bits is for the
 * B->A frame.  You allocate a 15-byte buffer
 * for each direction, and this function fills
 * it in. */
void run(byte AtoBkeystream[], byte BtoAkeystream[]) {
        int i;

        /* Zero out the output buffers. */
        for (i=0; i<=113/8; i++)
                AtoBkeystream[i] = BtoAkeystream[i] = 0;

        /* Generate 114 bits of keystream for the
         * A->B direction.  Store it, MSB first. */
        for (i=0; i<114; i++) {
                clock(0,0);
                AtoBkeystream[i/8] |= getbit() << (7-(i&7));
        }

        /* Generate 114 bits of keystream for the
         * B->A direction.  Store it, MSB first. */
        for (i=0; i<114; i++) {
                clock(0,0);
                BtoAkeystream[i/8] |= getbit() << (7-(i&7));
        }
}

/* Test the code by comparing it against
 * a known-good test vector. */
 
void test() {
#ifndef A5_2
        byte key[8] = {0x12, 0x23, 0x45, 0x67, 0x89, 0xAB, 0xCD, 0xEF};
        word frame = 0x134;
        byte goodAtoB[15] = { 0x53, 0x4E, 0xAA, 0x58, 0x2F, 0xE8, 0x15,
                              0x1A, 0xB6, 0xE1, 0x85, 0x5A, 0x72, 0x8C, 0x00 };
        byte goodBtoA[15] = { 0x24, 0xFD, 0x35, 0xA3, 0x5D, 0x5F, 0xB6,
                              0x52, 0x6D, 0x32, 0xF9, 0x06, 0xDF, 0x1A, 0xC0 };
#else /* A5_2 */
        byte key[8] = {0x00, 0xfc, 0xff, 0xff, 0xff, 0xff, 0xff, 0xff};
        word frame = 0x21;
        byte goodAtoB[15] = { 0xf4, 0x51, 0x2c, 0xac, 0x13, 0x59, 0x37,
                              0x64, 0x46, 0x0b, 0x72, 0x2d, 0xad, 0xd5, 0x00 };
        byte goodBtoA[15] = { 0x48, 0x00, 0xd4, 0x32, 0x8e, 0x16, 0xa1,
                              0x4d, 0xcd, 0x7b, 0x97, 0x22, 0x26, 0x51, 0x00 };
#endif /* A5_2 */
        byte AtoB[15], BtoA[15];
        int i, failed=0;

        keysetup(key, frame);
        run(AtoB, BtoA);

        /* Compare against the test vector. */
        for (i=0; i<15; i++)
                if (AtoB[i] != goodAtoB[i])
                        failed = 1;
        for (i=0; i<15; i++)
                if (BtoA[i] != goodBtoA[i])
                        failed = 1;

        /* Print some debugging output. */
        printf("key: 0x");
        for (i=0; i<8; i++)
                printf("%02X", key[i]);
        printf("\n");
        printf("frame number: 0x%06X\n", (unsigned int)frame);
        printf("known good output:\n");
        printf(" A->B: 0x");
        for (i=0; i<15; i++)
                printf("%02X", goodAtoB[i]);
        printf("  B->A: 0x");
        for (i=0; i<15; i++)
                printf("%02X", goodBtoA[i]);
        printf("\n");
        printf("observed output:\n");
        printf(" A->B: 0x");
        for (i=0; i<15; i++)
                printf("%02X", AtoB[i]);
        printf("  B->A: 0x");
        for (i=0; i<15; i++)
                printf("%02X", BtoA[i]);
        printf("\n");

        if (!failed) {
                printf("Self-check succeeded: everything looks ok.\n");
                exit(0);
        } else {
                /* Problems!  The test vectors didn't compare*/
                printf("\nI don't know why this broke; contact the authors.\n");
        }
}

int main(void) {
        test();
        return 0;
}