Найти вторую цифру заданного числа - C (СИ)

#include <stdio.h>
#include <math.h>
 
#define digits(n) ( (int)log10(n) + 1 )
 
int main(void) {
    unsigned n, a, b, c;
    
    printf("Number: ");
    scanf("%u", &n);
    printf("A = ");
    scanf("%u", &a);
    printf("B = ");
    scanf("%u", &b);
    printf("C = ");
    scanf("%u", &c);
    
    if ( n < 10 )
        printf("Number %u contain only one digit.\n", n);
    else
        printf("The second digit is %u\n", n / (int)pow(10, digits(n) - 2) % 10);
    
    printf("%sevided into %u evenly\n", ( n % a ) ? "Don't d" : "D", a);
    printf("%sevided into %u evenly\n", ( n % b ) ? "Don't d" : "D", b);
    printf("%sevided into %u evenly\n", ( n % c ) ? "Don't d" : "D", c);
    
    return 0;
}