Определить количество и процентное соотношение положительных, отрицательных и нулевых элементов - C (СИ)

#include <stdio.h>
#include <time.h>
#include <Windows.h>
 
#define LOW_BORDER  -99
#define HIGH_BORDER  99
 
int main(int argc, char *argv[])
{
    srand(time(NULL));
    int *arr, min, i, size;
    int count_neg = 0, count_zero = 0, count_pos = 0, count_sum;
    printf("Enter the number of elements in array\n");
    scanf("%d", &size);
 
    arr = malloc(size * sizeof(int));
 
    printf("Randomly generated array of %d elements:\n", size);
    for (i = 0; i < size; i++) {
        arr[i] = rand() % (HIGH_BORDER + 1 - LOW_BORDER) + LOW_BORDER;
        printf("%2d ", arr[i]);
    }
    for (i = 0; i < size; i++) {
        if (arr[i] > 0) {
            count_pos++;
        }
        else if (arr[i] < 0) {
            count_neg++;
        }
        else if (arr[i] == 0) {
            count_zero++;
        }
    }
    count_sum = count_pos + count_neg + count_zero;
    printf("\nThe number of positive elements is %d, what is %f percents\n", count_pos, ((double)count_pos / count_sum) * 100);
    printf("The number of positive elements is %d, what is %f percents\n", count_neg,   ((double)count_neg / count_sum) * 100);
    printf("The number of positive elements is %d, what is %f percents\n", count_zero,  ((double)count_zero / count_sum) * 100);
    system("pause");
    return 0;
}