Index out of range+ - C#
Формулировка задачи:
string[] FN = new string[5] { "Иван", "Евгений", "Михаил", "Илья", "Марк" };
string[] SN = new string[5] { "Кужелев", "Иванов", "Петров", "Сидоров", "Антонов" };
string[] MFN = new string[2] { "Никита", "Артем" };
string[] MSN = new string[2] { "Руденко", "Коверга" };
string fileName = "base.xml";
Random rnd = new Random();
int fn, sn, mfn, msn;
int cikl;
cikl = rnd.Next(20, 50);
XDocument doc = new XDocument();
XElement[] emp = new XElement[cikl];
for (int i = 0; i <= cikl; i++){
fn = rnd.Next(1, 6);
sn = rnd.Next(1, 6);
mfn = rnd.Next(1, 3);
msn = rnd.Next(1, 3);
emp[i] = new XElement("employee",
new XElement("fname", FN[fn]),
new XElement("sname", SN[sn]),
new XElement("mfname", MFN[mfn]),
new XElement("msname", MSN[msn])
);
} emp[i] = new XElement("employee",
new XElement("fname", FN[fn]),
new XElement("sname", SN[sn]),
new XElement("mfname", MFN[mfn]),
new XElement("msname", MSN[msn])
);Решение задачи: «Index out of range+»
textual
Листинг программы
XDocument doc = new XDocument();
XElement root = new XElement("employers");
doc.Add(root);
XElement[] emp = new XElement[cikl];
for (int i = 0; i < cikl; i++)
{
fn = rnd.Next(5);
sn = rnd.Next(5);
mfn = rnd.Next(2);
msn = rnd.Next(2);
emp[i] = new XElement("employee",
new XElement("fname", FN[fn]),
new XElement("sname", SN[sn]),
new XElement("mfname", MFN[mfn]),
new XElement("msname", MSN[msn])
);
root.Add(emp[i]);
}
doc.Save(fileName);