Как осуществить вывод Console.WriteLine() отдельным классом - C#

Формулировка задачи:

Вот пример программы

static void Main(string[] args)
    {
        ListFiltering();
        Console.ReadLine();
    }
 
    private static void ListFiltering()
    {
        var PersonList = new List<Person>();
 
        PersonList.Add(new Person() { Age = 23, Name = "Jon", Gender = "M" }); //Non-Constructor Object Property Initialization
        PersonList.Add(new Person() { Age = 24, Name = "Jack", Gender = "M" });
        PersonList.Add(new Person() { Age = 29, Name = "Billy", Gender = "M" });
 
        PersonList.Add(new Person() { Age = 33, Name = "Bob", Gender = "M" });
        PersonList.Add(new Person() { Age = 45, Name = "Frank", Gender = "M" });
 
        PersonList.Add(new Person() { Age = 24, Name = "Anna", Gender = "F" });
        PersonList.Add(new Person() { Age = 29, Name = "Sue", Gender = "F" });
        PersonList.Add(new Person() { Age = 35, Name = "Sally", Gender = "F" });
        PersonList.Add(new Person() { Age = 36, Name = "Jane", Gender = "F" });
        PersonList.Add(new Person() { Age = 42, Name = "Jill", Gender = "F" });
 
        //Logic: Show me all males that are less than 30 years old.
 
        Console.WriteLine("");
        //Iterative Method
        Console.WriteLine("List Filter Normal Way:");
        foreach (var p in PersonList)
            if (p.Gender == "M" && p.Age < 30)
                Console.WriteLine(p.Name + " is " + p.Age);
 
        Console.WriteLine("");
        //Lambda Filter Method
        Console.WriteLine("List Filter Lambda Way");
        foreach (var p in PersonList.Where(p => (p.Gender == "M" && p.Age < 30))) //.Where is an extension method
            Console.WriteLine(p.Name + " is " + p.Age);
 
        Console.WriteLine("");
        //LINQ Query Method
        Console.WriteLine("List Filter LINQ Way:");
        foreach (var v in from p in PersonList
                          where p.Gender == "M" && p.Age < 30
                          select new { p.Name, p.Age })
            Console.WriteLine(v.Name + " is " + v.Age);
    }
 
    private class Person
    {
        public Person() { }
        public int Age { get; set; }
        public string Name { get; set; }
        public string Gender { get; set; }
    }

Как осуществить вывод Console.WriteLine() отдельным классом? Я попытался сделать вот так

static void Main(string[] args)
    {
        ListFiltering();
        Console.ReadLine();
    }
 
        public static List<Person> ListFiltering()
    {
        var PersonList = new List<Person>();
 
        PersonList.Add(new Person() { Age = 23, Name = "Jon", Gender = "M" }); //Non-Constructor Object Property Initialization
        PersonList.Add(new Person() { Age = 24, Name = "Jack", Gender = "M" });
        PersonList.Add(new Person() { Age = 29, Name = "Billy", Gender = "M" });
 
        PersonList.Add(new Person() { Age = 33, Name = "Bob", Gender = "M" });
        PersonList.Add(new Person() { Age = 45, Name = "Frank", Gender = "M" });
 
        PersonList.Add(new Person() { Age = 24, Name = "Anna", Gender = "F" });
        PersonList.Add(new Person() { Age = 29, Name = "Sue", Gender = "F" });
        PersonList.Add(new Person() { Age = 35, Name = "Sally", Gender = "F" });
        PersonList.Add(new Person() { Age = 36, Name = "Jane", Gender = "F" });
        PersonList.Add(new Person() { Age = 42, Name = "Jill", Gender = "F" });
 
            return PersonList();

class Iterative_Method
    {
        public void Iterative()
        {
            Console.WriteLine("List Filter Normal Way:");
            foreach (var p in Program.ListFiltering())
                if (p.Gender == "M" && p.Age < 30)
                    Console.WriteLine(p.Name + " is " + p.Age);
        }
    } 
 
    private class Person
    {
        public Person() { }
        public int Age { get; set; }
        public string Name { get; set; }
        public string Gender { get; set; }
    }

компилятор выдает ошибку Ошибка 1 "PersonList" является "переменная", но используется как "метод" Как создать глобальный объект?

Решение задачи: «Как осуществить вывод Console.WriteLine() отдельным классом»

textual
                            Листинг программы 
                        

                            private static void Main(string[] args)
        {
            ListFiltering();
            Iterative_Method method= new Iterative_Method();
            method.Iterative();
            Console.ReadLine();
        }
 
        public static List<Person> ListFiltering()
        {
            var PersonList = new List<Person>();
 
            PersonList.Add(new Person() { Age = 23, Name = "Jon", Gender = "M" });
            //Non-Constructor Object Property Initialization
            PersonList.Add(new Person() { Age = 24, Name = "Jack", Gender = "M" });
            PersonList.Add(new Person() { Age = 29, Name = "Billy", Gender = "M" });
 
            PersonList.Add(new Person() { Age = 33, Name = "Bob", Gender = "M" });
            PersonList.Add(new Person() { Age = 45, Name = "Frank", Gender = "M" });
 
            PersonList.Add(new Person() { Age = 24, Name = "Anna", Gender = "F" });
            PersonList.Add(new Person() { Age = 29, Name = "Sue", Gender = "F" });
            PersonList.Add(new Person() { Age = 35, Name = "Sally", Gender = "F" });
            PersonList.Add(new Person() { Age = 36, Name = "Jane", Gender = "F" });
            PersonList.Add(new Person() { Age = 42, Name = "Jill", Gender = "F" });
 
            return PersonList;
        }
 
        class Iterative_Method
            { 
            public void Iterative ()
                {
                    Console.WriteLine("List Filter Normal Way:");
                    foreach (var p in Program.ListFiltering()) if (p.Gender == "M" && p.Age < 30) Console.WriteLine(p.Name + " is " + p.Age);
                }
            }
 
        public class Person
            {
            public Person(){}
            public int Age {get;set;}
            public string Name {get;set;}
            public string Gender {get;set;}
            }
        
    }
                        