Преобразование файла в формат XML путём сериализации - C#

public class Person
    {
 
        public string Name { get; set; }
        public string SName { get; set; }
        public string OName { get; set; }
        public string Mail { get; set; }
 
        public Person()
 
        { }
 
        public Person(string name, string sname, string oname, string mail)
        {
 
            Name = name;
            SName = sname;
            OName = oname;
            Mail = mail;
 
        }
 
    }
 
    class Program
    {
 
        static void Main(string[] args)
        {
 
            string filename = @"C:\test\1.txt";
 
            string line;
 
            Person person;
            person = new Person();
      //     Person[] people = new Person[] { person };
 
            XmlSerializer formatter = new XmlSerializer(typeof(Person));
 
            StreamReader sr = new StreamReader(@filename);
 
while (!sr.EndOfStream)
{
   line = sr.ReadLine();
   string[] ss = line.Split(';');
   Console.WriteLine(ss[0]);
   Console.WriteLine(ss[1]);
   Console.WriteLine(ss[2]);
   Console.WriteLine(ss[3]);
   Console.WriteLine("------------");
   person.Name = ss[0];
   person.SName = ss[1];
   person.OName = ss[2];
   person.Mail = ss[3];
 
   using (FileStream fs = new FileStream(@"C:\test\people1.xml", FileMode.OpenOrCreate))
   {
       formatter.Serialize(fs, person);
   }
 
}      
                sr.Close();