Можно ли как-то отловить NetSend, до того как он высветится - VB

Формулировка задачи:

Мне нужно отловить NetSend и отобразить его содержание у себя в программе, а само окно Службы сообщений, показывать не надо. Кто знает как сделать хоть какую-либо часть этой программы, пишите

Решение задачи: «Можно ли как-то отловить NetSend, до того как он высветится»

textual
                            Листинг программы 
                        

                            Private Declare Function FindWindow Lib "user32" Alias "FindWindowA" (ByVal lpClassName As String, ByVal lpWindowName As String) As Long
Private Declare Function BringWindowToTop Lib "user32" (ByVal hwnd As Long) As Long
Private Declare Function GetWindow Lib "user32" (ByVal hwnd As Long, ByVal wCmd As Long) As Long
Private Declare Function GetWindowTextLength Lib "user32" Alias "GetWindowTextLengthA" (ByVal hwnd As Long) As Long
Private Declare Function GetWindowText Lib "user32" Alias "GetWindowTextA" (ByVal hwnd As Long, ByVal lpString As String, ByVal cch As Long) As Long
Private Declare Function SendMessage Lib "user32" Alias "SendMessageA" (ByVal hwnd As Long, ByVal wMsg As Long, ByVal wParam As Long, lParam As Any) As Long
Private Declare Function FindWindowEx Lib "user32" Alias "FindWindowExA" (ByVal hWnd1 As Long, ByVal hWnd2 As Long, ByVal lpsz1 As String, ByVal lpsz2 As String) As Long
Const BM_CLICK = &HF5
Const WM_GETTEXTLENGTH = &HE
Private Const WM_GETTEXT = &HD
 
Private Sub Timer1_Timer()
Dim lWin As Long
Dim Control As Long
Dim text As String
Dim textlen As Long
lWin = FindWindow(vbNullString, "Messenger Service ")
If lWin <> 0 Then
  Control = FindWindowEx(lWin, 0, "Static", vbNullString)
      textlen = SendMessage(Control, WM_GETTEXTLENGTH, vbNull, vbNull)
      textlen = textlen + 1
  text = Space$(textlen)
  Call SendMessage(Control&, WM_GETTEXT, textlen, ByVal text)
  
  Control = FindWindowEx(lWin, 0, "Button", vbNullString)
  SendMessage Control, BM_CLICK, 0, 0
  List1.AddItem text
End If
End Sub
                        