Ошибка при открытии файла Excel с xlApp.Visible = False - VB

Dim fDialog As Office.FileDialog
Dim varFile As Variant
'Dim xlApp As Object  xlWB As Object, xlSheet As Object
Dim xlApp As Excel.Application
Dim xlWB As Excel.Workbook
Dim xlSheet As Excel.Worksheet
Dim val As Variant, tt As String
Dim prNum As String, subjCode As String, expertCode As String, EGEDate As String

Dim score As Variant, a As String, aa As String
Dim i As Integer, j As Integer, k As Integer
Dim rsCheck As Recordset

    Set xlApp = CreateObject("Excel.Application")
    xlApp.Visible = False

   ' Set up the File Dialog.
   Set fDialog = Application.FileDialog(msoFileDialogFilePicker)

   With fDialog

      ' Allow user to make multiple selections in dialog box
      .AllowMultiSelect = False
            
      ' Set the title of the dialog box.
      .Title = "Выберите файл протокола"

      ' Clear out the current filters, and add our own.
      .Filters.Clear
      .Filters.Add "Excel files", "*.xlsx"
      .Filters.Add "Excel files", "*.xls"

     If .Show = True Then

         'Loop through each file selected and add it to our list box.
         For Each varFile In .SelectedItems
            filetoOpen = varFile
         Next[sub][/sub]

      Else
         'MsgBox "You clicked Cancel in the file dialog box."
         GoTo end_
      End If
   End With

'xlApp.Visible = True
'xlApp.Visible = False

Set xlWB = xlApp.Workbooks.Open(filetoOpen)
Set xlSheet = xlWB.Worksheets(1)

'Бла-бла-бла (чтение ячеек)

xlWB.Close True
MsgBox ("Из файла считано " & (i - 5) & " результатов.")

end_:

xlApp.Quit
Set xlApp = Nothing