Перетаскивание объектов на форме мышью - VB

Формулировка задачи:

Нужно сделать такое же, только в VB 6:

Option Explicit
 
Const SNAP! = 5
Dim Xdown!, Ydown!
 
Private Sub Label1_MouseDown(ByVal Button As Integer, ByVal Shift As Integer, ByVal X As Single, ByVal Y As Single)
 
'Без этой процедуры можно обойтись, но с ней
'мышка чуть быстрее "зацепляет" объект
 
Xdown = X: Ydown = Y
End Sub
 
Private Sub Label1_MouseMove(ByVal Button As Integer, ByVal Shift As Integer, ByVal X As Single, ByVal Y As Single)
Dim l!, t!
If Button = 1 Then
    With Label1
        .Left = Application.Min(Application.Max(.Left - Xdown + X, 0), Me.Width - .Width - 5!)
        .Top = Application.Min(Application.Max(.Top - Ydown + Y, 0), Me.Height - .Height - 19!)
        If Abs(.Left - Label2.Left) <= SNAP And Abs(.Top - Label2.Top) <= SNAP Then
            .Left = Label2.Left
            .Top = Label2.Top
        End If
    End With
Else
    Xdown = X: Ydown = Y
End If
End Sub

Решение задачи: «Перетаскивание объектов на форме мышью»

textual
                            Листинг программы 
                        

                            Const SNAP! = 500
Dim Xdown!, Ydown!, bX As Single, bY As Single
 
 
Private Sub Form_Load()
    bX = Label1.Left: bY = Label1.Top
End Sub
 
Private Sub Label1_MouseDown(Button As Integer, Shift As Integer, X As Single, Y As Single)
Xdown = X: Ydown = Y
 
End Sub
 
Private Sub Label1_MouseMove(Button As Integer, Shift As Integer, X As Single, Y As Single)
Dim l!, t!
If Button = 1 Then
    With Label1
       .Move .Left - Xdown + X, .Top - Ydown + Y
        If Abs(.Left - Label2.Left) <= SNAP And Abs(.Top - Label2.Top) <= SNAP Then
            MsgBox "Столкновение"
            .Left = bX
            .Top = bY
            '.Left = Label2.Left
            '.Top = Label2.Top
        End If
    End With
Else
    Xdown = X: Ydown = Y
End If
End Sub
                        