Решить нелинейное уравнение и построить график - VB

Option Explicit
 
Private Sub Command1_Click()
     Dim x As Double, x0 As Double, x1 As Double, a As Double, b As Double, e As Double
     Dim iteraz As Integer, s As String, s1 As String, i As Integer
     Me.Height = 7800
     x1 = InputBox("Введите приближённое(1) значение X=", , 2)
     e = InputBox("Введите точность(0.0001) e=", , 0.0001)
     Picture1.Cls: Picture2.Cls: Picture3.Cls: Picture4.Cls
     Picture4.AutoRedraw = True: Picture4.FillStyle = 0
     iteraz = 0: x = x1
     Do
          iteraz = iteraz + 1
          x0 = x1
          x1 = fun(x0)
          Picture1.Print Format(x0, "##.00000")
          Picture2.Print Format(x1, "##.00000")
     Loop Until (Abs(x1 - x0) <= e)
     
     Picture4.DrawStyle = 0: Picture4.DrawWidth = 2
     Picture4.Scale (-1, x + 2)-(iteraz + 1, -1)
     Picture4.Line (-1, 0)-(iteraz + 1, 0), vbBlue
     Picture4.Line (0, -1)-(0, x + 2), vbBlue
     
     For i = 0 To iteraz
          Picture4.DrawStyle = 0: Picture4.DrawWidth = 3
          Picture4.Line (i, -(x / 100))-(i, (x / 100)), 0
          Picture4.DrawStyle = 2: Picture4.DrawWidth = 1
          Picture4.Line (i, -1)-(i, x + 2), 0
          Picture4.CurrentY = -0.1: Picture4.CurrentX = i: Picture4.Print i
     Next i
     
     For i = 1 To x + 2
           Picture4.DrawStyle = 0: Picture4.DrawWidth = 3
           Picture4.Line (-(iteraz / 100), i)-((iteraz / 100), i), 0
           Picture4.DrawStyle = 2: Picture4.DrawWidth = 1
           Picture4.Line (-1, i)-(iteraz + 2, i), 0
           Picture4.CurrentX = -0.5: Picture4.CurrentY = i: Picture4.Print i
     Next i
     
     Picture4.DrawStyle = 0: Picture4.DrawWidth = 3
     For i = 1 To iteraz
           x0 = x: x = fun(x0)
           Picture4.Line (i - 1, x0)-(i, x), vbRed
           Picture4.Circle (i, x), 0.1, vbBlue
           Picture4.Print Round(x, 3)
     Next i
     
     s = s & "Вычисленное значение корня:" & x1 & vbCrLf
     s = s & "Число итераций:" & iteraz
     Picture3.Print s
End Sub
 
Private Function fun(x As Double) As Double
    fun = Log(x) + 1.8
End Function